(b^2/2+b^2)^0.5-b=0

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Solution for (b^2/2+b^2)^0.5-b=0 equation: 



(b^2/2+b^2)^0.5-b=0



Domain of the equation: 2+b^2)^0.5!=0

We move all terms containing b to the left, all other terms to the right

b^2)^0.5!=-2

b!=-2/1

b!=-2

b∈R



We add all the numbers together, and all the variables

(b^2/2+b^2)^0.5-1b=0

We multiply all the terms by the denominator


(b^2-1b*2+b^2)^0.5=0

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